решить все

1) ((5 * 4⁻²)⁰ + (1/6)⁻¹) / 3 + (1/2)⁻² = 0 + 6 / 3 + 4 = 6/7

(5 * 4⁻²)⁰ = 1 (любое число в степени 0 равно 1)
(1/6)⁻¹ = 6
(1/2)⁻² = 2² = 4

2) (3⁻² + 2⁻¹) / (1/3)⁻² + (-2)⁻¹ *4 + (1/2)⁻² = (11/18) / (1/9 + 2) = (11/18) / (19/9) = 11 * 9 / 18 * 19 = 11 / 38

(3⁻² + 2⁻¹) = 1/9 + 1/2 = 11/18
(1/3)⁻² = 1/9
(-2)⁻¹ *4 = -2
(1/2)⁻² = 4

3) 2⁻³ + (8/7)⁻¹ + (2*3⁻²)⁰ / (3⁻² - (3/2)⁻¹) * (1/5)⁻¹ = 2 / (1/9 - 2/3) * 5 = 2 / (-5/9) * 5 = 2 * 9 / - 5 * 5 = - 18/25

(2*3⁻²)⁰ = 1
(8/7)⁻¹ = 7/8
2⁻³ = 1/8

3⁻² = 1/9
(1/5)⁻¹ = 5
(3/2)⁻¹ = 2/3