Первое задание:
${1\frac{9}{12} = \frac{12+9}{12} = \frac{21}{12} = \frac{7}{4}}$
${\frac{7}{4} * 3 = \frac{21}{4}}$
${\frac{3}{6} * \frac{7}{21} = \frac{1}{2} * \frac{1}{3} = \frac{1}{6}}$
${6 - \frac{21}{4} + \frac{1}{6} = \frac{6*12 - 3*21 + 2}{12} = \frac{11}{12}}$
Второе задание:
${(\frac{3}{4})^{3} = \frac{3^{3}}{4^{3}} = \frac{27}{64}}$
${1\frac{9}{12} = \frac{12+9}{12} = \frac{21}{12} = \frac{7}{4}}$
${\frac{7}{4} * 3 = \frac{21}{4}}$
${\frac{3}{6} * \frac{7}{21} = \frac{1}{2} * \frac{1}{3} = \frac{1}{6}}$
${6 - \frac{21}{4} + \frac{1}{6} = \frac{6*12 - 3*21 + 2}{12} = \frac{11}{12}}$
Второе задание:
${(\frac{3}{4})^{3} = \frac{3^{3}}{4^{3}} = \frac{27}{64}}$
- 1 комментарий
- Отметить нарушение!
-
Спасибо вам большое! !отметить нарушение!Lilly